The average bus between Old Kent Road and North Finchley takes 1h 1m and the fastest bus takes 54 min. The bus service runs several times per day from Old Kent Road to North Finchley. The journey time may be longer on weekends and holidays; use the search form on this page to search for a specific travel date.
Buses run every 4 hours between Old Kent Road and North Finchley. The earliest departure is at 12:00 AM at night, and the last departure from Old Kent Road is at 11:57 PM which arrives into North Finchley at 12:59 AM. All services require a transfer, and take on average 1h 1m. The schedules shown below are for the next available departures.

1h 4m • 1 change

1h • 1 change

57 min • 1 change

57 min • 1 change

59 min • 1 change

1h 4m • 1 change

1h • 1 change

57 min • 1 change

59 min • 1 change

1h 4m • 1 change

1h • 1 change

57 min • 1 change

59 min • 1 change

1h 4m • 1 change

1h • 1 change

57 min • 1 change

1h 1m • 1 change

1h 6m • 1 change

1h • 1 change

54 min • 1 change

1h 5m • 1 change

1h • 1 change

56 min • 1 change

57 min • 1 change
Want to know about travelling from Old Kent Road to North Finchley? We have put together a list of the most frequently asked questions from our users such as: What is the cheapest mode of transport? What is the quickest option? How much do tickets usually cost? and many more.
No, there is no direct bus from Old Kent Road to North Finchley. However, there are services departing from Old Kent Road station and arriving at North Finchley station via Finsbury Square. The journey, including transfers, takes approximately 1h 1m.
Old Kent Road to North Finchley bus services, operated by Go Ahead London, depart from Dunton Road station.
Old Kent Road to North Finchley bus services, operated by Go Ahead London, arrive at Christchurch Avenue North Finchley station.
The distance between Old Kent Road and North Finchley is 15.4 km. The road distance is 19 km.
You can take a bus from Dunton Road to Christchurch Avenue North Finchley via Finsbury Square in around 1h 25m.