The average bus between Samut Prakan and Buri Ram takes 7h 15m and the fastest bus takes 6h 47m. The bus service runs several times per day from Samut Prakan to Buri Ram. The journey time may be longer on weekends and holidays; use the search form on this page to search for a specific travel date.
Buses run every 2 hours between Samut Prakan and Buri Ram. The earliest departure is at 7:02 AM in the morning, and the last departure from Samut Prakan is at 9:37 PM which arrives into Buri Ram at 4:45 AM. All services require a transfer at รพ.ทหารผ่านศึก;Veterans General Hospital and take an average of 7h 15m. The schedules shown below are for the next available departures.


7h 23m • 2 changes

7h 27m • 2 changes

7h 12m • 2 changes

7h 22m • 2 changes

7h 23m • 2 changes

7h 27m • 2 changes

7h 12m • 2 changes

7h 22m • 2 changes

7h 23m • 2 changes

7h 27m • 2 changes

7h 12m • 2 changes

7h 22m • 2 changes

7h 33m • 2 changes

7h 48m • 2 changes

7h 33m • 2 changes

7h 18m • 2 changes

7h 33m • 2 changes

7h 48m • 2 changes

7h 33m • 2 changes

7h 18m • 2 changesWant to know about travelling from Samut Prakan to Buri Ram? We have put together a list of the most frequently asked questions from our users such as: What is the cheapest mode of transport? What is the quickest option? How much do tickets usually cost? and many more.
No, there is no direct bus from Samut Prakan to Buri Ram. However, there are services departing from Samut Prakan station and arriving at Buri Ram station via Buriram. The journey, including transfers, takes approximately 7h 15m.
Samut Prakan to Buri Ram bus services, operated by Department of Land Transport, depart from Bangkok Nakon Chai Air Bus Station.
Samut Prakan to Buri Ram bus services, operated by Department of Land Transport, arrive at Buriram station.
The distance between Samut Prakan and Buri Ram is 311.5 km. The road distance is 416 km.
Nakhonchai Air operates a bus from Bangkok Nakon Chai Air Bus Station to Buriram every 2 hours. Tickets cost ฿460–550 and the journey takes 5h 50m.