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AC Hotel Córdoba by Marriott to Seville trains

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Trip Overview

The average train between AC Hotel Córdoba by Marriott and Seville takes 1h 2m and the fastest train takes 52 min. The train runs at least 2 times per hour from AC Hotel Córdoba by Marriott to Seville. The journey time may be longer on weekends and holidays; use the search form on this page to search for a specific travel date.

1h 2m
Duration
127 km
Distance
€19
Average price
Every 30 minutes
Frequency

AC Hotel Córdoba by Marriott to Seville train times

Trains run every 30 minutes between AC Hotel Córdoba by Marriott and Seville. The earliest departure is at 8:13 AM in the morning, and the last departure from AC Hotel Córdoba by Marriott is at 11:03 PM which arrives into Seville at 11:57 PM. All services run direct with no transfers required, and take on average 1h 2m. The schedules shown below are for the next available departures.

Frequently asked questions

Want to know about travelling from AC Hotel Córdoba by Marriott to Seville? We have put together a list of the most frequently asked questions from our users such as: What is the cheapest mode of transport? What is the quickest option? How much do tickets usually cost? and many more.

Map of how to get from AC Hotel Córdoba by Marriott to Seville.ExpandLaunch map view
  • Distance: 127 km
  • Duration: 1h 2m

What companies run services between AC Hotel Córdoba by Marriott, Spain and Seville, Spain?

Renfe Viajeros operates a train from Cordoba-Central to Sevilla-Santa Justa every 30 minutes. Tickets cost €16–25 and the journey takes 54 min. Three other operators also service this route.

Operators