The average train between Barons Court Underground Station and Stanmore Underground Station takes 52 min and the fastest train takes 49 min. The train runs at least 13 times per hour from Barons Court Underground Station to Stanmore Underground Station. The journey time may be longer on weekends and holidays; use the search form on this page to search for a specific travel date.
Trains run every 5 minutes between Barons Court Underground Station and Stanmore Underground Station. The earliest departure is at 8:11 AM in the morning, and the last departure from Barons Court Underground Station is at 12:13 PM which arrives into Stanmore Underground Station at 1:05 PM. All services require a transfer, and take on average 52 min. The schedules shown below are for the next available departures.

49 min • 1 change

51 min • 1 change

49 min • 1 change

51 min • 1 change
Want to know about travelling from Barons Court Underground Station to Stanmore Underground Station? We have put together a list of the most frequently asked questions from our users such as: What is the cheapest mode of transport? What is the quickest option? How much do tickets usually cost? and many more.
No, there is no direct train from Barons Court Underground Station to Stanmore Underground Station. However, there are services departing from Barons Court Underground Station station and arriving at Stanmore Underground Station station via Green Park station station. The journey, including transfers, takes approximately 52 min.
Barons Court Underground Station to Stanmore Underground Station train services, operated by London Underground (Tube), depart from Barons Court station.
Barons Court Underground Station to Stanmore Underground Station train services, operated by London Underground (Tube), arrive at Stanmore station.
The distance between Barons Court Underground Station and Stanmore Underground Station is 15.5 km. The road distance is 27 km.
You can take a subway from Barons Court station to Stanmore station via Green Park station in around 48 min.