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Besançon to Clervaux trains

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Trip Overview

The average train between Besançon and Clervaux takes 8h 36m and the fastest train takes 6h 36m. The train service runs several times per day from Besançon to Clervaux. The journey time may be longer on weekends and holidays; use the search form on this page to search for a specific travel date.

8h 36m
Duration
513 km
Distance
€125
Average price
Twice daily
Frequency

Besançon to Clervaux train times

Trains run twice daily between Besançon and Clervaux. The earliest departure is at 9:38 AM in the morning, and the last departure from Besançon is at 7:57 PM which arrives into Clervaux at 8:14 AM. All services require a transfer at Besancon-Franche Comte Tgv and take an average of 8h 36m. The schedules shown below are for the next available departures.

Frequently asked questions

Want to know about travelling from Besançon to Clervaux? We have put together a list of the most frequently asked questions from our users such as: What is the cheapest mode of transport? What is the quickest option? How much do tickets usually cost? and many more.

Map of how to get from Besançon to Clervaux.ExpandLaunch map view
  • Distance: 513 km
  • Duration: 8h 36m

What companies run services between Besançon, France and Clervaux, Luxembourg?

You can take a train from Besancon Viotte to Clervaux via Besancon-Franche Comte Tgv and Luxembourg in around 6h 18m.

Operators