The average train between Canterbury and Earl's Court Underground Station takes 1h 20m and the fastest train takes 1h 18m. There is a train service every few hours from Canterbury to Earl's Court Underground Station. The journey time may be longer on weekends and holidays; use the search form on this page to search for a specific travel date.
Trains run hourly between Canterbury and Earl's Court Underground Station. The earliest departure is at 5:20 AM in the morning, and the last departure from Canterbury is at 10:23 PM which arrives into Earl's Court Underground Station at 11:41 PM. All services require a transfer at London St Pancras International and take an average of 1h 20m. The schedules shown below are for the next available departures.

1h 20m • 1 change

1h 21m • 1 change

1h 24m • 1 change

1h 20m • 1 change

1h 28m • 1 change

1h 18m • 1 change

1h 18m • 1 change

1h 19m • 1 change

1h 28m • 1 change

1h 18m • 1 change

1h 18m • 1 change

1h 19m • 1 change
Want to know about travelling from Canterbury to Earl's Court Underground Station? We have put together a list of the most frequently asked questions from our users such as: What is the cheapest mode of transport? What is the quickest option? How much do tickets usually cost? and many more.
No, there is no direct train from Canterbury to Earl's Court Underground Station. However, there are services departing from Canterbury station and arriving at Earl's Court Underground Station station via London St Pancras Intl. The journey, including transfers, takes approximately 1h 20m.
Canterbury to Earl's Court Underground Station train services, operated by Southeastern, depart from Canterbury West station.
Canterbury to Earl's Court Underground Station train services, operated by Southeastern, arrive at Earl's Court station.
The distance between Canterbury and Earl's Court Underground Station is 91.5 km. The road distance is 121 km.
Southeastern operates a train from Canterbury East to London Victoria hourly. Tickets cost £30–65 and the journey takes 1h 34m.