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Cleveland to Jefferson City trains

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Trip Overview

The average train between Cleveland and Jefferson City takes 15h 45m and the fastest train takes 15h 33m. There is at least one train per day from Cleveland to Jefferson City. The journey time may be longer on weekends and holidays; use the search form on this page to search for a specific travel date.

15h 45m
Duration
741 mi
Distance
$480
Average price
Once daily
Frequency

Cleveland to Jefferson City train times

Trains run once daily between Cleveland and Jefferson City. The earliest departure is at 1:59 AM at night, and the last departure from Cleveland is at 3:03 AM which arrives into Jefferson City at 5:36 PM. All services require a transfer, and take on average 15h 45m. The schedules shown below are for the next available departures.

Departing Thursday, October 29, 2026

  •  → 

    AmtrakAmtrak15h 37m • 1 change

Departing Friday, October 30, 2026

  •  → 

    AmtrakAmtrak15h 37m • 1 change

Departing Saturday, October 31, 2026

  •  → 

    AmtrakAmtrak15h 37m • 1 change

Departing Sunday, November 1, 2026

  •  → 

    AmtrakAmtrak15h 33m • 1 change

Departing Monday, November 2, 2026

  •  → 

    AmtrakAmtrak16h 37m • 1 change

Departing Tuesday, November 3, 2026

  •  → 

    AmtrakAmtrak15h 37m • 1 change

Frequently asked questions

Want to know about travelling from Cleveland to Jefferson City? We have put together a list of the most frequently asked questions from our users such as: What is the cheapest mode of transport? What is the quickest option? How much do tickets usually cost? and many more.

Map of how to get from Cleveland to Jefferson City.ExpandLaunch map view
  • Distance: 741.5 mi
  • Duration: 15h 45m

What companies run services between Cleveland, OH, USA and Jefferson City, MO, USA?

You can take a train from Cleveland Amtrak to Jefferson City Station via Chicago Union Station in around 15h 32m.

Operators