The average train between Cleveland and Sanford takes 36h 5m and the fastest train takes 32h 11m. The train runs, on average, 5 times per week from Cleveland to Sanford. The journey time may be longer on weekends and holidays; use the search form on this page to search for a specific travel date.
Trains run 5 times a week between Cleveland and Sanford. The earliest departure is at 1:54 AM at night, and the last departure from Cleveland is at 1:54 AM which arrives into Sanford at 10:05 AM. All services require a transfer, and take on average 36h 5m. The schedules shown below are for the next available departures.
Want to know about travelling from Cleveland to Sanford? We have put together a list of the most frequently asked questions from our users such as: What is the cheapest mode of transport? What is the quickest option? How much do tickets usually cost? and many more.
No, there is no direct train from Cleveland to Sanford. However, there are services departing from Cleveland station and arriving at Sanford station via Deland. The journey, including transfers, takes approximately 36h 5m.
Cleveland to Sanford train services, operated by Amtrak, depart from Cleveland Amtrak station.
Cleveland to Sanford train services, operated by Amtrak, arrive at Deland station.
The distance between Cleveland and Sanford is 1,412.6 km. The road distance is 2,160 km.
Amtrak operates a train from Cleveland Amtrak to Deland once daily. Tickets cost $420–900 and the journey takes 30h 59m.
