The average train between Edgware Road and Kennington Station takes 17 min and the fastest train takes 15 min. The train runs at least 18 times per hour from Edgware Road to Kennington Station. The journey time may be longer on weekends and holidays; use the search form on this page to search for a specific travel date.
Trains run every 5 minutes between Edgware Road and Kennington Station. The earliest departure is at 12:02 AM at night, and the last departure from Edgware Road is at 11:57 PM which arrives into Kennington Station at 12:16 AM. All services require a transfer at Marble Arch station and take an average of 17 min. The schedules shown below are for the next available departures.

18 min • 1 change
16 min • 1 change
16 min • 1 change
17 min • 1 change
17 min • 1 change
21 min • 1 change
18 min • 1 change
3h 10m • 1 change
19 min • 1 change
16 min • 1 change
20 min • 1 change
20 min • 1 change
20 min • 1 change
18 min • 1 change
17 min • 1 change
18 min • 1 change
20 min • 1 change
18 min • 1 change
17 min • 1 change
18 min • 1 changeWant to know about travelling from Edgware Road to Kennington Station? We have put together a list of the most frequently asked questions from our users such as: What is the cheapest mode of transport? What is the quickest option? How much do tickets usually cost? and many more.
No, there is no direct train from Edgware Road to Kennington Station. However, there are services departing from Marble Arch station and arriving at Kennington station via Tottenham Court Road station. The journey, including transfers, takes approximately 17 min.
Edgware Road to Kennington Station train services, operated by London Underground (Tube), depart from Marble Arch station.
Edgware Road to Kennington Station train services, operated by London Underground (Tube), arrive at Kennington station.
The distance between Edgware Road and Kennington Station is 4.7 km.
You can take a vehicle from Edgware Road to Kennington station via Marble Arch station and Tottenham Court Road station in around 16 min.