- Distance: 5.4 mi
- Duration: 32 min
The average train between Faneuil Hall and AC Hotel by Marriott Boston Cleveland Circle takes 32 min and the fastest train takes 27 min. The train runs at least 11 times per hour from Faneuil Hall to AC Hotel by Marriott Boston Cleveland Circle. The journey time may be longer on weekends and holidays; use the search form on this page to search for a specific travel date.
Trains run every 5 minutes between Faneuil Hall and AC Hotel by Marriott Boston Cleveland Circle. The earliest departure is at 12:27 AM at night, and the last departure from Faneuil Hall is at 9:37 AM which arrives into AC Hotel by Marriott Boston Cleveland Circle at 10:07 AM. All services run direct with no transfers required, and take on average 32 min. The schedules shown below are for the next available departures.
Want to know about travelling from Faneuil Hall to AC Hotel by Marriott Boston Cleveland Circle? We have put together a list of the most frequently asked questions from our users such as: What is the cheapest mode of transport? What is the quickest option? How much do tickets usually cost? and many more.
Yes, there is a direct train departing from Faneuil Hall station and arriving at AC Hotel by Marriott Boston Cleveland Circle station. Services depart every 5 minutes, and operate Once daily. The journey takes approximately 32 min.
Faneuil Hall to AC Hotel by Marriott Boston Cleveland Circle train services, operated by MBTA, depart from Government Center station.
Faneuil Hall to AC Hotel by Marriott Boston Cleveland Circle train services, operated by MBTA, arrive at Cleveland Circle station.
The distance between Faneuil Hall and AC Hotel by Marriott Boston Cleveland Circle is 8.2 km. The road distance is 9 km.
MBTA operates a vehicle from Government Center to Cleveland Circle every 5 minutes. Tickets cost $3 and the journey takes 35 min.
