- Distance: 38.4 mi
- Duration: 59 min
The average train between Fort Edward and Schenectady takes 59 min and the fastest train takes 56 min. The train service runs several times per day from Fort Edward to Schenectady. The journey time may be longer on weekends and holidays; use the search form on this page to search for a specific travel date.
Trains run twice daily between Fort Edward and Schenectady. The earliest departure is at 1:00 PM in the afternoon, and the last departure from Fort Edward is at 5:33 PM which arrives into Schenectady at 6:36 PM. All services run direct with no transfers required, and take on average 59 min. The schedules shown below are for the next available departures.
Want to know about travelling from Fort Edward to Schenectady? We have put together a list of the most frequently asked questions from our users such as: What is the cheapest mode of transport? What is the quickest option? How much do tickets usually cost? and many more.
Yes, there is a direct train departing from Fort Edward station and arriving at Schenectady station. Services depart twice daily, and operate Once daily. The journey takes approximately 59 min.
Fort Edward to Schenectady train services, operated by Amtrak, depart from Fort Edward Amtrak station.
Fort Edward to Schenectady train services, operated by Amtrak, arrive at Schenectady station.
Book your Fort Edward to Schenectady train tickets online with Amtrak.
The distance between Fort Edward and Schenectady is 58 km. The road distance is 62 km.
Amtrak operates a train from Fort Edward Amtrak to Schenectady twice daily. Tickets cost $12–26 and the journey takes 56 min.
