- Distance: 11.1 mi
- Duration: 24 min
The average train between Jenkintown and Jefferson Station takes 24 min and the fastest train takes 20 min. The train runs at least 3 times per hour from Jenkintown to Jefferson Station. The journey time may be longer on weekends and holidays; use the search form on this page to search for a specific travel date.
Trains run every 20 minutes between Jenkintown and Jefferson Station. The earliest departure is at 4:25 AM at night, and the last departure from Jenkintown is at 11:55 PM which arrives into Jefferson Station at 12:15 AM. All services run direct with no transfers required, and take on average 24 min. The schedules shown below are for the next available departures.
Want to know about travelling from Jenkintown to Jefferson Station? We have put together a list of the most frequently asked questions from our users such as: What is the cheapest mode of transport? What is the quickest option? How much do tickets usually cost? and many more.
Yes, there is a direct train departing from Jenkintown-Wyncote station and arriving at Jefferson Station. Services depart every 20 minutes, and operate every day. The journey takes approximately 24 min.
Jenkintown to Jefferson Station train services, operated by SEPTA, depart from Jenkintown-Wyncote station.
Jenkintown to Jefferson Station train services, operated by SEPTA, arrive at Jefferson Station.
The distance between Jenkintown and Jefferson Station is 16.2 km. The road distance is 17 km.
SEPTA operates a train from Jenkintown-Wyncote to Jefferson Station every 20 minutes. Tickets cost $2–4 and the journey takes 25 min.
