The average train between Kirkby-in-Ashfield and Melton Mowbray takes 2h 21m and the fastest train takes 1h 36m. There is a train service every few hours from Kirkby-in-Ashfield to Melton Mowbray. The journey time may be longer on weekends and holidays; use the search form on this page to search for a specific travel date.
Trains run hourly between Kirkby-in-Ashfield and Melton Mowbray. The earliest departure is at 6:21 AM in the morning, and the last departure from Kirkby-in-Ashfield is at 11:24 PM which arrives into Melton Mowbray at 6:30 AM. All services require a transfer at Nottingham and take an average of 2h 21m. The schedules shown below are for the next available departures.


2h 15m • 2 changes


1h 36m • 2 changes


2h 9m • 2 changes


2h 8m • 2 changes


2h 15m • 2 changes


1h 36m • 2 changes


2h 9m • 2 changes


2h 8m • 2 changes


2h 15m • 2 changes


1h 36m • 2 changes


2h 9m • 2 changes


2h 8m • 2 changes
Want to know about travelling from Kirkby-in-Ashfield to Melton Mowbray? We have put together a list of the most frequently asked questions from our users such as: What is the cheapest mode of transport? What is the quickest option? How much do tickets usually cost? and many more.
No, there is no direct train from Kirkby-in-Ashfield to Melton Mowbray. However, there are services departing from Kirkby-in-Ashfield station and arriving at Melton Mowbray station via Nottingham. The journey, including transfers, takes approximately 2h 21m.
Kirkby-in-Ashfield to Melton Mowbray train services, operated by East Midlands Railways, depart from Kirkby in Ashfield station.
Kirkby-in-Ashfield to Melton Mowbray train services, operated by East Midlands Railways, arrive at Leicester station.
Book your Kirkby-in-Ashfield to Melton Mowbray train tickets online with East Midlands Railways and Cross Country.
The distance between Kirkby-in-Ashfield and Melton Mowbray is 44.2 km. The road distance is 89 km.
You can take a train from Kirkby in Ashfield to Melton Mowbray via Nottingham and Leicester in around 2h 22m.