The average train between Lancaster and Kensington takes 3h 30m and the fastest train takes 2h 54m. There is a train service every few hours from Lancaster to Kensington. The journey time may be longer on weekends and holidays; use the search form on this page to search for a specific travel date.
Trains run hourly between Lancaster and Kensington. The earliest departure is at 5:13 AM in the morning, and the last departure from Lancaster is at 8:59 PM which arrives into Kensington at 5:58 AM. All services require a transfer at London Euston and take an average of 3h 30m. The schedules shown below are for the next available departures.
Arrives next day

3h 24m • 1 change
Arrives next day

4h 40m • 1 change

3h 11m • 1 change

2h 58m • 1 change

3h 19m • 1 change

3h 20m • 1 change

2h 56m • 1 change

3h 19m • 1 change

3h 21m • 1 change

3h 21m • 1 change

3h 9m • 1 change

2h 56m • 1 change

3h 19m • 1 change

3h 20m • 1 change

3h 9m • 1 change

2h 58m • 1 change

3h 19m • 1 change

3h 20m • 1 change
Want to know about travelling from Lancaster to Kensington? We have put together a list of the most frequently asked questions from our users such as: What is the cheapest mode of transport? What is the quickest option? How much do tickets usually cost? and many more.
No, there is no direct train from Lancaster to Kensington. However, there are services departing from Lancaster station and arriving at Kensington station via London Euston. The journey, including transfers, takes approximately 3h 30m.
Lancaster to Kensington train services, operated by Avanti West Coast, depart from Lancaster station.
Lancaster to Kensington train services, operated by Avanti West Coast, arrive at London Euston station.
Book your Lancaster to Kensington train tickets online with Avanti West Coast and London Underground (Tube).
The distance between Lancaster and Kensington is 332.9 km. The road distance is 376 km.
Avanti West Coast operates a train from Lancaster to London Euston hourly. Tickets cost £80–140 and the journey takes 2h 33m.