The average train between Lansdale and Secaucus Junction takes 2h 54m and the fastest train takes 2h 17m. There is a train service every few hours from Lansdale to Secaucus Junction. The journey time may be longer on weekends and holidays; use the search form on this page to search for a specific travel date.
Trains run hourly between Lansdale and Secaucus Junction. The earliest departure is at 5:09 AM in the morning, and the last departure from Lansdale is at 11:14 PM which arrives into Secaucus Junction at 5:03 AM. All services require a transfer at Jefferson Station and take an average of 2h 54m. The schedules shown below are for the next available departures.



2h 54m • 3 changes



2h 54m • 3 changes



2h 44m • 3 changes



3h 32m • 3 changes



2h 42m • 3 changes



2h 41m • 3 changes



2h 40m • 3 changes



2h 26m • 3 changes



2h 42m • 3 changes



2h 41m • 3 changes



2h 40m • 3 changes



2h 26m • 3 changes
Want to know about travelling from Lansdale to Secaucus Junction? We have put together a list of the most frequently asked questions from our users such as: What is the cheapest mode of transport? What is the quickest option? How much do tickets usually cost? and many more.
No, there is no direct train from Lansdale to Secaucus Junction. However, there are services departing from Lansdale station and arriving at Secaucus Junction station via Jefferson Station station. The journey, including transfers, takes approximately 2h 54m.
Lansdale to Secaucus Junction train services, operated by SEPTA, depart from Lansdale station.
Lansdale to Secaucus Junction train services, operated by SEPTA, arrive at Newark Penn Station.
The distance between Lansdale and Secaucus Junction is 117.4 km. The road distance is 180 km.
You can take a train from Lansdale to Secaucus Upper Level via Jefferson Station, 11th St, Drexel Station at 30th St, 30th Street Station, and Newark Penn Station in around 2h 33m.