The average train between Lansdale and Secaucus Junction takes 3h 1m and the fastest train takes 2h 32m. There is a train service every few hours from Lansdale to Secaucus Junction. The journey time may be longer on weekends and holidays; use the search form on this page to search for a specific travel date.
Trains run hourly between Lansdale and Secaucus Junction. The earliest departure is at 5:09 AM in the morning, and the last departure from Lansdale is at 11:14 PM which arrives into Secaucus Junction at 5:56 AM. All services require a transfer at Jefferson Station and take an average of 3h 1m. The schedules shown below are for the next available departures.



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2h 40m • 3 changesWant to know about travelling from Lansdale to Secaucus Junction? We have put together a list of the most frequently asked questions from our users such as: What is the cheapest mode of transport? What is the quickest option? How much do tickets usually cost? and many more.
No, there is no direct train from Lansdale to Secaucus Junction. However, there are services departing from Lansdale station and arriving at Newark Penn Station via Jefferson Station. The journey, including transfers, takes approximately 3h 1m.
Lansdale to Secaucus Junction train services, operated by SEPTA, depart from Lansdale station.
Lansdale to Secaucus Junction train services, operated by Amtrak, arrive at Newark Penn Station.
The distance between Lansdale and Secaucus Junction is 117.4 km. The road distance is 133 km.
You can take a train from Lansdale to Secaucus Upper Level via Jefferson Station, 11th St, Drexel Station at 30th St, 30th Street Station, and Newark Penn Station in around 2h 36m.