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Lansdale to Secaucus Junction trains

Find Transport to Secaucus Junction

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Trip Overview

The average train between Lansdale and Secaucus Junction takes 2h 52m and the fastest train takes 2h 17m. There is an hourly train service from Lansdale to Secaucus Junction. The journey time may be longer on weekends and holidays; use the search form on this page to search for a specific travel date.

2h 52m
Duration
112 mi
Distance
$300
Average price
Hourly
Frequency

Train

best
  1. Take the train from Lansdale to Jefferson Stationtrain train Lan
  2. Take the train from 30th Street Station to Newark Penn Stationtrain train Keystone Service / ...
2h 33m
$26–616

Lansdale to Secaucus Junction train times

Trains run hourly between Lansdale and Secaucus Junction. The earliest departure is at 5:09 AM in the morning, and the last departure from Lansdale is at 11:14 PM which arrives into Secaucus Junction at 5:03 AM. All services require a transfer at Jefferson Station and take an average of 2h 52m. The schedules shown below are for the next available departures.

Frequently asked questions

Want to know about travelling from Lansdale to Secaucus Junction? We have put together a list of the most frequently asked questions from our users such as: What is the cheapest mode of transport? What is the quickest option? How much do tickets usually cost? and many more.

Map of how to get from Lansdale to Secaucus Junction.ExpandLaunch map view
  • Distance: 111.7 mi
  • Duration: 2h 52m

What companies run services between Lansdale, PA, USA and Secaucus Junction, NJ, USA?

You can take a train from Lansdale to Secaucus Upper Level via Jefferson Station, 11th St, Drexel Station at 30th St, 30th Street Station, and Newark Penn Station in around 2h 33m.

Operators