- Distance: 14.9 mi
- Duration: 42 min
The average train between Little Falls and Secaucus Junction takes 42 min and the fastest train takes 40 min. The train service runs several times per day from Little Falls to Secaucus Junction. The journey time may be longer on weekends and holidays; use the search form on this page to search for a specific travel date.
Trains run every 2 hours between Little Falls and Secaucus Junction. The earliest departure is at 5:10 AM in the morning, and the last departure from Little Falls is at 11:11 PM which arrives into Secaucus Junction at 11:51 PM. All services run direct with no transfers required, and take on average 42 min. The schedules shown below are for the next available departures.
Want to know about travelling from Little Falls to Secaucus Junction? We have put together a list of the most frequently asked questions from our users such as: What is the cheapest mode of transport? What is the quickest option? How much do tickets usually cost? and many more.
Yes, there is a direct train departing from Little Falls station and arriving at Secaucus Junction station. Services depart every 2 hours, and operate 5 times a week. The journey takes approximately 42 min.
Little Falls to Secaucus Junction train services, operated by NJ Transit, depart from Msu station.
Little Falls to Secaucus Junction train services, operated by NJ Transit, arrive at Secaucus Upper Level station.
The distance between Little Falls and Secaucus Junction is 16.4 km. The road distance is 24 km.
NJ Transit operates a train from Msu to Secaucus Upper Level every 2 hours. Tickets cost $2–12 and the journey takes 43 min.