The average train between Market Harborough and Banbury takes 2h 58m and the fastest train takes 2h 16m. There is a train service every few hours from Market Harborough to Banbury. The journey time may be longer on weekends and holidays; use the search form on this page to search for a specific travel date.
Trains run hourly between Market Harborough and Banbury. The earliest departure is at 6:24 AM in the morning, and the last departure from Market Harborough is at 11:29 PM which arrives into Banbury at 12:53 PM. All services require a transfer at Leicester and take an average of 2h 58m. The schedules shown below are for the next available departures.
Arrives next day


11h 50m • 2 changes
Arrives next day


13h 24m • 2 changes


2h 46m • 2 changes


2h 35m • 2 changes


2h 42m • 2 changes


2h 29m • 2 changes


2h 32m • 2 changes


2h 16m • 2 changes


2h 40m • 2 changes


2h 46m • 2 changes


2h 32m • 2 changes


2h 16m • 2 changes


2h 40m • 2 changes


2h 46m • 2 changes
Want to know about travelling from Market Harborough to Banbury? We have put together a list of the most frequently asked questions from our users such as: What is the cheapest mode of transport? What is the quickest option? How much do tickets usually cost? and many more.
No, there is no direct train from Market Harborough to Banbury. However, there are services departing from Market Harborough station and arriving at Banbury station via Birmingham New Street. The journey, including transfers, takes approximately 2h 58m.
Market Harborough to Banbury train services, operated by East Midlands Railways, depart from Leicester station.
Market Harborough to Banbury train services, operated by East Midlands Railways, arrive at Banbury station.
Book your Market Harborough to Banbury train tickets online with East Midlands Railways and Cross Country.
The distance between Market Harborough and Banbury is 54.3 km. The road distance is 166 km.
You can take a train from Market Harborough to Banbury via Leicester and Birmingham New Street in around 2h 55m.