- Distance: 14.1 mi
- Duration: 30 min
The average train between Meadowbrook Station (SEPTA) and Jefferson Station takes 30 min and the fastest train takes 28 min. There is a train service every few hours from Meadowbrook Station (SEPTA) to Jefferson Station. The journey time may be longer on weekends and holidays; use the search form on this page to search for a specific travel date.
Trains run hourly between Meadowbrook Station (SEPTA) and Jefferson Station. The earliest departure is at 5:42 AM in the morning, and the last departure from Meadowbrook Station (SEPTA) is at 11:47 PM which arrives into Jefferson Station at 12:15 AM. All services run direct with no transfers required, and take on average 30 min. The schedules shown below are for the next available departures.
Want to know about travelling from Meadowbrook Station (SEPTA) to Jefferson Station? We have put together a list of the most frequently asked questions from our users such as: What is the cheapest mode of transport? What is the quickest option? How much do tickets usually cost? and many more.
Yes, there is a direct train departing from Meadowbrook Station (SEPTA) station and arriving at Jefferson Station station. Services depart hourly, and operate Once daily. The journey takes approximately 30 min.
Meadowbrook Station (SEPTA) to Jefferson Station train services, operated by SEPTA, depart from Meadowbrook station.
Meadowbrook Station (SEPTA) to Jefferson Station train services, operated by SEPTA, arrive at Jefferson Station.
The distance between Meadowbrook Station (SEPTA) and Jefferson Station is 18.5 km. The road distance is 23 km.
SEPTA operates a train from Meadowbrook to Jefferson Station hourly. Tickets cost $3 and the journey takes 31 min.
