The average train between Mineola Station (LIRR) and Hewlett takes 50 min and the fastest train takes 37 min. There is an hourly train service from Mineola Station (LIRR) to Hewlett. The journey time may be longer on weekends and holidays; use the search form on this page to search for a specific travel date.
Trains run hourly between Mineola Station (LIRR) and Hewlett. The earliest departure is at 12:00 AM at night, and the last departure from Mineola Station (LIRR) is at 11:22 PM which arrives into Hewlett at 12:03 AM. All services require a transfer, and take on average 50 min. The schedules shown below are for the next available departures.

48 min • 1 change

48 min • 1 change
Arrives next day

41 min • 1 change

48 min • 1 change

53 min • 1 change

42 min • 1 change

46 min • 1 change

38 min • 1 change

1h 21m • 1 change

2h 10m • 1 change

1h 1m • 1 change
Want to know about travelling from Mineola Station (LIRR) to Hewlett? We have put together a list of the most frequently asked questions from our users such as: What is the cheapest mode of transport? What is the quickest option? How much do tickets usually cost? and many more.
No, there is no direct train from Mineola Station (LIRR) to Hewlett. However, there are services departing from Mineola Station (LIRR) station and arriving at Hewlett station via Jamaica. The journey, including transfers, takes approximately 50 min.
Mineola Station (LIRR) to Hewlett train services, operated by Long Island Rail Road, depart from Mineola station.
Mineola Station (LIRR) to Hewlett train services, operated by Long Island Rail Road, arrive at Gibson station.
The distance between Mineola Station (LIRR) and Hewlett is 11.7 km. The road distance is 26 km.
You can take a train from Mineola to Gibson via Jamaica in around 50 min.