- Distance: 44.2 mi
- Duration: 1h 14m
The average train between Montauk and Remsenburg-Speonk takes 1h 14m and the fastest train takes 1h 10m. The train service runs several times per day from Montauk to Remsenburg-Speonk. The journey time may be longer on weekends and holidays; use the search form on this page to search for a specific travel date.
Trains run every 4 hours between Montauk and Remsenburg-Speonk. The earliest departure is at 1:09 AM at night, and the last departure from Montauk is at 10:03 PM which arrives into Remsenburg-Speonk at 11:24 PM. All services run direct with no transfers required, and take on average 1h 14m. The schedules shown below are for the next available departures.
Want to know about travelling from Montauk to Remsenburg-Speonk? We have put together a list of the most frequently asked questions from our users such as: What is the cheapest mode of transport? What is the quickest option? How much do tickets usually cost? and many more.
Yes, there is a direct train departing from Montauk station and arriving at Remsenburg-Speonk station. Services depart every 4 hours, and operate Once daily. The journey takes approximately 1h 14m.
Montauk to Remsenburg-Speonk train services, operated by Long Island Rail Road, depart from Montauk station.
Montauk to Remsenburg-Speonk train services, operated by Long Island Rail Road, arrive at Speonk station.
The distance between Montauk and Remsenburg-Speonk is 68.6 km. The road distance is 71 km.
Long Island Rail Road operates a train from Montauk to Speonk hourly. Tickets cost $12–27 and the journey takes 1h 11m.
