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Montbéliard to La Chaux-de-Fonds trains

Find Transport to La Chaux-de-Fonds

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Trip Overview

The average train between Montbéliard and La Chaux-de-Fonds takes 4h 22m and the fastest train takes 3h 3m. The train service runs several times per day from Montbéliard to La Chaux-de-Fonds. The journey time may be longer on weekends and holidays; use the search form on this page to search for a specific travel date.

4h 22m
Duration
163 km
Distance
CHF 30
Average price
3 times a day
Frequency

Train

best
  1. Take the train from Montbeliard to Besancon Viottetrain train Ter
  2. Take the train from Besancon Viotte to La Chaux-De-Fondstrain train Ter
3h 46m
CHF 25–51

Montbéliard to La Chaux-de-Fonds train times

Trains run 3 times a day between Montbéliard and La Chaux-de-Fonds. The earliest departure is at 6:19 AM in the morning, and the last departure from Montbéliard is at 8:54 PM which arrives into La Chaux-de-Fonds at 6:54 AM. All services require a transfer, and take on average 4h 22m. The schedules shown below are for the next available departures.

Frequently asked questions

Want to know about travelling from Montbéliard to La Chaux-de-Fonds? We have put together a list of the most frequently asked questions from our users such as: What is the cheapest mode of transport? What is the quickest option? How much do tickets usually cost? and many more.

Map of how to get from Montbéliard to La Chaux-de-Fonds.ExpandLaunch map view
  • Distance: 163.3 km
  • Duration: 4h 22m

What companies run services between Montbéliard, France and La Chaux-de-Fonds, Switzerland?

You can take a train from Montbeliard to La Chaux-De-Fonds via Besancon Viotte in around 3h 46m.

Operators