The average train between Oxford and Harrow on the Hill takes 1h 37m and the fastest train takes 1h 19m. There is an hourly train service from Oxford to Harrow on the Hill. The journey time may be longer on weekends and holidays; use the search form on this page to search for a specific travel date.
Trains run hourly between Oxford and Harrow on the Hill. The earliest departure is at 5:20 AM in the morning, and the last departure from Oxford is at 11:00 PM which arrives into Harrow on the Hill at 8:08 AM. All services require a transfer at London Paddington and take an average of 1h 37m. The schedules shown below are for the next available departures.


1h 39m • 2 changes


1h 40m • 2 changes


1h 40m • 2 changes


1h 37m • 2 changes


2h 15m • 2 changes


1h 36m • 2 changes


1h 39m • 2 changes


1h 40m • 2 changes


1h 26m • 2 changes


1h 38m • 2 changes


1h 20m • 2 changes


1h 38m • 2 changes
Want to know about travelling from Oxford to Harrow on the Hill? We have put together a list of the most frequently asked questions from our users such as: What is the cheapest mode of transport? What is the quickest option? How much do tickets usually cost? and many more.
No, there is no direct train from Oxford to Harrow on the Hill. However, there are services departing from Oxford station and arriving at Harrow on the Hill station via London Paddington. The journey, including transfers, takes approximately 1h 37m.
Oxford to Harrow on the Hill train services, operated by Great Western Railway (GWR), depart from Oxford station.
Oxford to Harrow on the Hill train services, operated by Great Western Railway (GWR), arrive at London Paddington station.
Book your Oxford to Harrow on the Hill train tickets online with Great Western Railway (GWR), London Underground (Tube) and Chiltern Railways.
The distance between Oxford and Harrow on the Hill is 66.2 km. The road distance is 117 km.
Great Western Railway (GWR) operates a train from Oxford to London Paddington every 30 minutes. Tickets cost £28–55 and the journey takes 54 min.