- Distance: 12.2 mi
- Duration: 24 min
The average train between Roselle Park and Secaucus Junction takes 24 min and the fastest train takes 22 min. The train service runs several times per day from Roselle Park to Secaucus Junction. The journey time may be longer on weekends and holidays; use the search form on this page to search for a specific travel date.
Trains run every 4 hours between Roselle Park and Secaucus Junction. The earliest departure is at 9:29 AM in the morning, and the last departure from Roselle Park is at 9:31 PM which arrives into Secaucus Junction at 9:57 PM. All services run direct with no transfers required, and take on average 24 min. The schedules shown below are for the next available departures.
Want to know about travelling from Roselle Park to Secaucus Junction? We have put together a list of the most frequently asked questions from our users such as: What is the cheapest mode of transport? What is the quickest option? How much do tickets usually cost? and many more.
Yes, there is a direct train departing from Roselle Park station and arriving at Secaucus Junction station. Services depart every 4 hours, and operate 5 times a week. The journey takes approximately 24 min.
Roselle Park to Secaucus Junction train services, operated by NJ Transit, depart from Roselle Park station.
Roselle Park to Secaucus Junction train services, operated by NJ Transit, arrive at Secaucus Upper Level station.
The distance between Roselle Park and Secaucus Junction is 19.1 km. The road distance is 20 km.
NJ Transit operates a train from Roselle Park to Secaucus Upper Level every 4 hours. Tickets cost $2–11 and the journey takes 25 min.