- Distance: 28.2 mi
- Duration: 47 min
The average train between Rutgers University–New Brunswick and Secaucus Junction takes 47 min and the fastest train takes 31 min. The train runs at least 2 times per hour from Rutgers University–New Brunswick to Secaucus Junction. The journey time may be longer on weekends and holidays; use the search form on this page to search for a specific travel date.
Trains run every 30 minutes between Rutgers University–New Brunswick and Secaucus Junction. The earliest departure is at 12:29 AM at night, and the last departure from Rutgers University–New Brunswick is at 11:27 PM which arrives into Secaucus Junction at 12:19 AM. All services run direct with no transfers required, and take on average 47 min. The schedules shown below are for the next available departures.
Want to know about travelling from Rutgers University–New Brunswick to Secaucus Junction? We have put together a list of the most frequently asked questions from our users such as: What is the cheapest mode of transport? What is the quickest option? How much do tickets usually cost? and many more.
Yes, there is a direct train departing from Rutgers University–New Brunswick station and arriving at Secaucus Junction station. Services depart every 30 minutes, and operate Once daily. The journey takes approximately 47 min.
Rutgers University–New Brunswick to Secaucus Junction train services, operated by NJ Transit, depart from New Brunswick station.
Rutgers University–New Brunswick to Secaucus Junction train services, operated by NJ Transit, arrive at Secaucus Upper Level station.
The distance between Rutgers University–New Brunswick and Secaucus Junction is 42.6 km. The road distance is 45 km.
NJ Transit operates a train from New Brunswick to Secaucus Upper Level every 30 minutes. Tickets cost $2–15 and the journey takes 51 min.