The average train between Sanford and Cleveland takes 34h 58m and the fastest train takes 31h 38m. The train runs, on average, 6 times per week from Sanford to Cleveland. The journey time may be longer on weekends and holidays; use the search form on this page to search for a specific travel date.
Trains run 6 times a week between Sanford and Cleveland. The earliest departure is at 7:15 PM in the evening, and the last departure from Sanford is at 11:15 PM which arrives into Cleveland at 2:53 AM. All services require a transfer, and take on average 34h 58m. The schedules shown below are for the next available departures.
Want to know about travelling from Sanford to Cleveland? We have put together a list of the most frequently asked questions from our users such as: What is the cheapest mode of transport? What is the quickest option? How much do tickets usually cost? and many more.
No, there is no direct train from Sanford to Cleveland. However, there are services departing from Sanford station and arriving at Cleveland station via Cleveland Amtrak. The journey, including transfers, takes approximately 34h 58m.
Sanford to Cleveland train services, operated by SunRail, depart from Deland station.
Sanford to Cleveland train services, operated by SunRail, arrive at Cleveland Amtrak station.
The distance between Sanford and Cleveland is 1,412.6 km. The road distance is 2,160 km.
Amtrak operates a train from Deland to Cleveland Amtrak once daily. Tickets cost $420–900 and the journey takes 31h 4m.
