- Distance: 38.4 mi
- Duration: 47 min
The train between Schenectady and Fort Edward takes 47 min. The train service runs several times per day from Schenectady to Fort Edward. The journey time may be longer on weekends and holidays; use the search form on this page to search for a specific travel date.
Trains run twice daily between Schenectady and Fort Edward. The earliest departure is at 12:08 PM in the afternoon, and the last departure from Schenectady is at 5:28 PM which arrives into Fort Edward at 6:16 PM. All services run direct with no transfers required, and take on average 47 min. The schedules shown below are for the next available departures.
Want to know about travelling from Schenectady to Fort Edward? We have put together a list of the most frequently asked questions from our users such as: What is the cheapest mode of transport? What is the quickest option? How much do tickets usually cost? and many more.
Yes, there is a direct train departing from Schenectady station and arriving at Fort Edward station. Services depart twice daily, and operate Once daily. The journey takes approximately 47 min.
Schenectady to Fort Edward train services, operated by Amtrak, depart from Schenectady station.
Schenectady to Fort Edward train services, operated by Amtrak, arrive at Fort Edward Amtrak station.
Book your Schenectady to Fort Edward train tickets online with Amtrak.
The distance between Schenectady and Fort Edward is 58 km. The road distance is 62 km.
Amtrak operates a train from Schenectady to Fort Edward Amtrak twice daily. Tickets cost $12–26 and the journey takes 47 min.
