The average train between Secaucus Junction and Port Jefferson takes 2h 45m and the fastest train takes 2h 14m. There is a train service every few hours from Secaucus Junction to Port Jefferson. The journey time may be longer on weekends and holidays; use the search form on this page to search for a specific travel date.
Trains run hourly between Secaucus Junction and Port Jefferson. The earliest departure is at 1:56 AM at night, and the last departure from Secaucus Junction is at 11:51 PM which arrives into Port Jefferson at 2:35 AM. All services require a transfer at New York Penn Station and take an average of 2h 45m. The schedules shown below are for the next available departures.


3h 11m • 2 changes


2h 39m • 2 changes


3h 9m • 2 changes


2h 29m • 2 changes


5h 52m • 2 changes


2h 35m • 2 changes


2h 25m • 2 changes


2h 32m • 2 changes


5h 59m • 2 changes


2h 34m • 2 changes


2h 25m • 2 changes


2h 31m • 2 changes


5h 59m • 2 changes


2h 34m • 2 changes


2h 25m • 2 changes


2h 31m • 2 changes
Want to know about travelling from Secaucus Junction to Port Jefferson? We have put together a list of the most frequently asked questions from our users such as: What is the cheapest mode of transport? What is the quickest option? How much do tickets usually cost? and many more.
No, there is no direct train from Secaucus Junction to Port Jefferson. However, there are services departing from Secaucus Junction station and arriving at Port Jefferson station via Huntington. The journey, including transfers, takes approximately 2h 45m.
Secaucus Junction to Port Jefferson train services, operated by NJ Transit, depart from New York Penn Station.
Secaucus Junction to Port Jefferson train services, operated by NJ Transit, arrive at Port Jefferson station.
The distance between Secaucus Junction and Port Jefferson is 87.1 km. The road distance is 104 km.
You can take a train from Secaucus Upper Level to Port Jefferson via New York Penn Station and Huntington in around 3h 7m.