- Distance: 12.2 mi
- Duration: 23 min
The train between Secaucus Junction and Roselle Park takes 23 min. The train service runs several times per day from Secaucus Junction to Roselle Park. The journey time may be longer on weekends and holidays; use the search form on this page to search for a specific travel date.
Trains run every 4 hours between Secaucus Junction and Roselle Park. The earliest departure is at 10:49 AM in the morning, and the last departure from Secaucus Junction is at 10:57 PM which arrives into Roselle Park at 11:20 PM. All services run direct with no transfers required, and take on average 23 min. The schedules shown below are for the next available departures.
Want to know about travelling from Secaucus Junction to Roselle Park? We have put together a list of the most frequently asked questions from our users such as: What is the cheapest mode of transport? What is the quickest option? How much do tickets usually cost? and many more.
Yes, there is a direct train departing from Secaucus Junction station and arriving at Roselle Park station. Services depart every 4 hours, and operate 5 times a week. The journey takes approximately 23 min.
Secaucus Junction to Roselle Park train services, operated by NJ Transit, depart from Secaucus Upper Level station.
Secaucus Junction to Roselle Park train services, operated by NJ Transit, arrive at Roselle Park station.
The distance between Secaucus Junction and Roselle Park is 19.1 km. The road distance is 20 km.
NJ Transit operates a train from Secaucus Upper Level to Roselle Park 5 times a day. Tickets cost $2–11 and the journey takes 23 min.