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Seefeld in Tirol to Belgrade trains

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Trip Overview

The average train between Seefeld in Tirol and Belgrade takes 22h 43m and the fastest train takes 22h 33m. The train runs, on average, 6 times per week from Seefeld in Tirol to Belgrade. The journey time may be longer on weekends and holidays; use the search form on this page to search for a specific travel date.

22h 43m
Duration
1,192 km
Distance
RSD 19,963
Average price
6 times a week
Frequency

Seefeld in Tirol to Belgrade train times

Trains run 6 times a week between Seefeld in Tirol and Belgrade. The earliest departure is at 10:16 AM in the morning, and the last departure from Seefeld in Tirol is at 10:46 AM which arrives into Belgrade at 9:19 AM. All services require a transfer at Innsbruck Hauptbahnhof and take an average of 22h 43m. The schedules shown below are for the next available departures.

Frequently asked questions

Want to know about travelling from Seefeld in Tirol to Belgrade? We have put together a list of the most frequently asked questions from our users such as: What is the cheapest mode of transport? What is the quickest option? How much do tickets usually cost? and many more.

Map of how to get from Seefeld in Tirol to Belgrade.ExpandLaunch map view
  • Distance: 1,191.9 km
  • Duration: 22h 43m

What companies run services between Seefeld in Tirol, Tyrol, Austria and Belgrade, Serbia?

You can take a train from Seefeld In Tirol to Beograd Centar via Innsbruck Hauptbahnhof, Wien Hbf, Budapest-Kelenfoeld, Szeged, and Subotica in around 16h 26m.

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