- Distance: 6.4 mi
- Duration: 19 min
The train between Shaw–Howard University Station and Tenleytown–AU Station takes 19 min. The train runs, on average, once a week from Shaw–Howard University Station to Tenleytown–AU Station. The journey time may be longer on weekends and holidays; use the search form on this page to search for a specific travel date.
Trains run on demand between Shaw–Howard University Station and Tenleytown–AU Station. Service times information will be available soon. All services run direct with no transfers required, and take on average 19 min.
Want to know about travelling from Shaw–Howard University Station to Tenleytown–AU Station? We have put together a list of the most frequently asked questions from our users such as: What is the cheapest mode of transport? What is the quickest option? How much do tickets usually cost? and many more.
No, there is no direct train from Shaw–Howard University Station to Tenleytown–AU Station. However, there are services departing from Shaw–Howard University Station station and arriving at Tenleytown–AU Station station via Tenleytown, Red Line Center Platform. The journey, including transfers, takes approximately 10,675,199d 2h.
Shaw–Howard University Station to Tenleytown–AU Station train services, operated by Washington Metropolitan Area Transit Authority, depart from Gallery Place, Red Line Track 2 Platform station.
Shaw–Howard University Station to Tenleytown–AU Station train services, operated by Washington Metropolitan Area Transit Authority, arrive at Tenleytown, Red Line Center Platform station.
The distance between Shaw–Howard University Station and Tenleytown–AU Station is 6.3 km. The road distance is 10 km.
Washington Metropolitan Area Transit Authority operates a subway from Gallery Place, Red Line Track 2 Platform to Tenleytown, Red Line Center Platform every 10 minutes. Tickets cost $2–3 and the journey takes 13 min.
