- Distance: 7.2 km
- Duration: 12 min
The average train between Square-Victoria–OACI Station and Jean-Talon Market takes 12 min and the fastest train takes 11 min. The train runs at least 10 times per hour from Square-Victoria–OACI Station to Jean-Talon Market. The journey time may be longer on weekends and holidays; use the search form on this page to search for a specific travel date.
Trains run every 10 minutes between Square-Victoria–OACI Station and Jean-Talon Market. The earliest departure is at 7:05 AM in the morning, and the last departure from Square-Victoria–OACI Station is at 10:42 AM which arrives into Jean-Talon Market at 10:54 AM. All services run direct with no transfers required, and take on average 12 min. The schedules shown below are for the next available departures.
Want to know about travelling from Square-Victoria–OACI Station to Jean-Talon Market? We have put together a list of the most frequently asked questions from our users such as: What is the cheapest mode of transport? What is the quickest option? How much do tickets usually cost? and many more.
Yes, there is a direct train departing from Square-Victoria–OACI Station station and arriving at Jean-Talon Market station. Services depart every 10 minutes, and operate Once daily. The journey takes approximately 12 min.
Square-Victoria–OACI Station to Jean-Talon Market train services, operated by Société de transport de Montréal, depart from Station Square-Victoria–OACI.
Square-Victoria–OACI Station to Jean-Talon Market train services, operated by Société de transport de Montréal, arrive at Station Jean-Talon.
The distance between Square-Victoria–OACI Station and Jean-Talon Market is 5.5 km. The road distance is 7 km.
Société de transport de Montréal operates a subway from Station Square-Victoria–OACI to Station Jean-Talon every 10 minutes. Tickets cost $4 and the journey takes 12 min.
