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Tenleytown–AU Station to Shaw–Howard University Station trains

Find Transport to Shaw–Howard University Station

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Trip Overview

The train between Tenleytown–AU Station and Shaw–Howard University Station takes 19 min. The train runs, on average, once a week from Tenleytown–AU Station to Shaw–Howard University Station. The journey time may be longer on weekends and holidays; use the search form on this page to search for a specific travel date.

19 min
Duration
6 mi
Distance
$4
Average price
On demand
Frequency

Tenleytown–AU Station to Shaw–Howard University Station train times

Trains run on demand between Tenleytown–AU Station and Shaw–Howard University Station. Service times information will be available soon. All services run direct with no transfers required, and take on average 19 min.

Frequently asked questions

Want to know about travelling from Tenleytown–AU Station to Shaw–Howard University Station? We have put together a list of the most frequently asked questions from our users such as: What is the cheapest mode of transport? What is the quickest option? How much do tickets usually cost? and many more.

Map of how to get from Tenleytown–AU Station to Shaw–Howard University Station.ExpandLaunch map view
  • Distance: 6.4 mi
  • Duration: 19 min

What companies run services between Tenleytown–AU Station, DC, USA and Shaw–Howard University Station, DC, USA?

You can take a subway from Tenleytown, Red Line Center Platform to Shaw-Howard, Green/Yellow Line Center Platform via Gallery Place, Red Line Track 1 Platform and Gallery Place, Green/Yellow Line Center Platform in around 19 min.

Operators