The average train between Villanova University and Secaucus Junction takes 2h 26m and the fastest train takes 1h 48m. There is an hourly train service from Villanova University to Secaucus Junction. The journey time may be longer on weekends and holidays; use the search form on this page to search for a specific travel date.
Trains run hourly between Villanova University and Secaucus Junction. The earliest departure is at 4:53 AM at night, and the last departure from Villanova University is at 11:10 PM which arrives into Secaucus Junction at 5:03 AM. All services require a transfer at Villanova and take an average of 2h 26m. The schedules shown below are for the next available departures.


3h 25m • 2 changes

2h 36m • 2 changes

2h 22m • 2 changes

2h 39m • 2 changes

2h 27m • 2 changes

1h 58m • 2 changes

2h 4m • 2 changes

2h 14m • 2 changes

2h 27m • 2 changes

1h 58m • 2 changes

2h 4m • 2 changes

2h 14m • 2 changesWant to know about travelling from Villanova University to Secaucus Junction? We have put together a list of the most frequently asked questions from our users such as: What is the cheapest mode of transport? What is the quickest option? How much do tickets usually cost? and many more.
No, there is no direct train from Villanova University to Secaucus Junction. However, there are services departing from Villanova University station and arriving at Secaucus Junction station via Gray 30th St Station station. The journey, including transfers, takes approximately 2h 26m.
Villanova University to Secaucus Junction train services, operated by SEPTA, depart from Villanova station.
Villanova University to Secaucus Junction train services, operated by SEPTA, arrive at Newark Penn Station.
The distance between Villanova University and Secaucus Junction is 134.2 km. The road distance is 155 km.
You can take a vehicle from Villanova University to Secaucus Upper Level via Villanova, 30th Street Station, and Newark Penn Station in around 2h 6m.