- Distance: 92.6 mi
- Duration: 1h 50m
The average train between Warrensburg and Jefferson City takes 1h 50m and the fastest train takes 1h 48m. The train service runs several times per day from Warrensburg to Jefferson City. The journey time may be longer on weekends and holidays; use the search form on this page to search for a specific travel date.
Trains run twice daily between Warrensburg and Jefferson City. The earliest departure is at 9:57 AM in the morning, and the last departure from Warrensburg is at 5:24 PM which arrives into Jefferson City at 7:12 PM. All services run direct with no transfers required, and take on average 1h 50m. The schedules shown below are for the next available departures.
Want to know about travelling from Warrensburg to Jefferson City? We have put together a list of the most frequently asked questions from our users such as: What is the cheapest mode of transport? What is the quickest option? How much do tickets usually cost? and many more.
Yes, there is a direct train departing from Warrensburg station and arriving at Jefferson City station. Services depart twice daily, and operate Once daily. The journey takes approximately 1h 50m.
Warrensburg to Jefferson City train services, operated by Amtrak, depart from Warrensburg Amtrak Station.
Warrensburg to Jefferson City train services, operated by Amtrak, arrive at Jefferson City Station.
Book your Warrensburg to Jefferson City train tickets online with Amtrak.
The distance between Warrensburg and Jefferson City is 137.2 km. The road distance is 149 km.
Amtrak operates a train from Warrensburg Amtrak Station to Jefferson City Station twice daily. Tickets cost $30–65 and the journey takes 1h 48m.
