Rome2Rio

How to get fromTinley Park to Griffithby bus, taxi, or car

Find Transport to Griffith

See all options

There are 5 ways to get from Tinley Park to Griffith by bus, taxi, or car

Select an option below to see step-by-step directions and to compare ticket prices and travel times in Rome2Rio's travel planner.

  1. Line 364 bus, taxi

    best
    1. Take the bus from 159th St & Ridgeland Ave to River Oaks Dr & Burnham Avebus bus 364
    2. Take the taxi from River Oaks Dr & Burnham Ave to Griffithtaxi taxi
    1h 14m
    $32–43
  2. Drive 22.7 mi

    cheapest
    1. Drive from Tinley Park to Griffithcar car 22.7 mi
    34 min
    $5–6
  3. Taxi

    1. Take the taxi from Tinley Park to Griffithtaxi taxi 22.7 mi
    34 min
    $65–80
  4. Line 364 bus, taxi via 6701 159th St

    1. Take the bus from 6701 159th St to River Oaks Dr & Burnham Avebus bus 364
    2. Take the taxi from River Oaks Dr & Burnham Ave to Griffithtaxi taxi
    1h 15m
    $32–43
  5. Line 364 bus, taxi via 159th St & Oak Park Ave

    1. Take the bus from 159th St & Oak Park Ave to River Oaks Dr & Burnham Avebus bus 364
    2. Take the taxi from River Oaks Dr & Burnham Ave to Griffithtaxi taxi
    1h 15m
    $32–43

Questions & Answers

What companies run services between Tinley Park, IL, USA and Griffith, IN, USA?

There is no direct connection from Tinley Park to Griffith. However, you can take the line 364 bus to River Oaks Dr & Burnham Ave then take the taxi to Griffith. Alternatively, you can drive from Tinley Park to Griffith in around 34 min.

Bus operators
Other operators

Want to know more about travelling around the world?

Rome2Rio's Travel Guide series provide vital information for the global traveller. Read our range of informative guides on popular transport routes and companies - including Travelling Croatia’s Dalmatian Coast by boat, bus, car and train, Which side of Niagara Falls should I choose (and how do I get there)?, and Thanksgiving 2018: How to travel stress-free - to help you get the most out of your next trip.